Explanation

579.Count Occurrences of a Value

Easy
Given an array nums and a target, return how many times the target appears. Counting combines a linear scan with a counter. Unlike searching, it can never stop early: every element might be another match, so an unsorted array always needs one full pass. (If the array were sorted, all copies would sit together and binary searchBinary SearchRepeatedly halving a sorted range to find a value in O(log n) steps. could find their range much faster.)

Example 1:

Input: nums = [3,7,3,1,3], target = 3

Output: 3

Example 2:

Input: nums = [3,7], target = 5

Output: 0

+ 4 hidden test cases run on Submit.

Constraints:

  • ●1 ≤ nums.length ≤ 1000
  • ●-1000000 ≤ nums[i], target ≤ 1000000

nums =

[3, 7, 3, 1, 3]

target =

3