Given a non-negative integer n, return every odd number from 1 up to and including n, in increasing order. The check-every-numberCheck Every NumberWalking through every integer from 1 to n and testing i % 2 != 0 before deciding whether to keep it. version mirrors the even-number check exactly, just flipping the condition. The step-by-2Step by 2Starting at 1 and incrementing by 2 each time, so every value visited is already odd. version again skips the wasted half of the work by construction, starting at 1 instead of 2.