Implement a Stack Using Two Queues
Implement stackOpsFromQueues
Implement a LIFO stackLIFOLast In, First Out — the most recently pushed element is always the first one popped. using only queue operationsQueue OperationsEnqueue (add to the back), dequeue (remove from the front), and peek the front — a queue is FIFO (First In, First Out), the opposite order from a stack. — enqueue at the back, dequeue from the front, peek the front — supporting
push(v), pop(), top(), isEmpty(), and size(). As with the array and linked-list versions, this takes a fixed sequence of operations and replays them, returning the result of every pop, top, isEmpty, and size call as an array.
A queue naturally hands back its oldest element first — the opposite of what a stack needs. Two classic techniques bridge that gap, and they're complementary rather than one strictly beating the other: rotate the queue after every push so the newest value ends up at the front (cheap pop, expensive push), or drain the queue down to just its last element whenever something needs to come off the top (cheap push, expensive pop). Neither approach avoids the reordering work a real stack never needs in the first place — they just disagree about which operation should pay for it.
Example 1:
Input: ops = ["push","push","push","pop","pop","top"], args = [5,10,15,0,0,0]
Output: [15,10,5]
Example 2:
Input: ops = ["isEmpty","push","isEmpty","pop","isEmpty"], args = [0,7,0,0,0]
Output: [1,0,7,1]
Example 3:
Input: ops = ["push","push","size","pop","size"], args = [1,2,0,0,0]
Output: [2,2,1]
+ 5 hidden test cases run on Submit.
Constraints:
- ●
1 ≤ number of operations ≤ 12 - ●
Each operation is one of push, pop, top, isEmpty, or size - ●
0 ≤ pushed value ≤ 1000 - ●
pop and top return -1 when the stack is empty - ●
Only queue operations (enqueue at the back, dequeue from the front, peek the front) may be used to store elements — no direct indexing into the middle - ●
This version replays a fixed sequence of operations and reports the result of every pop, top, isEmpty, and size call, in order (push has no return value)
ops =
["push", "push", "push", "pop", "pop", "top"]
args =
[5, 10, 15, 0, 0, 0]