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Print Multiple Lines in Java

beginner· Basics & I/O · Fundamentals

Problem

Each call to System.out.println() automatically adds a newline after the text it prints, so multiple calls appear on separate lines.

Print three separate lines of text to the console.

Input

—

Output

Line 1
Line 2
Line 3

Java Program

Java

public class PrintMultipleLines {
    public static void main(String[] args) {
        System.out.println("Line 1");
        System.out.println("Line 2");
        System.out.println("Line 3"); // each call starts on a fresh line
    }
}

▶ Run Code

Output

Line 1
Line 2
Line 3

Core Logic

Calling println() once per line is the most direct way to print several lines — each call ends with its own newline.

How It Works

1The first println("Line 1") prints the text and moves the cursor to a new line.
2The next println() call starts writing from that new line, and does the same again.
3Repeating the call for each line builds up the full multi-line output.

Three separate println() calls produce three separate lines in the console, in the order they were called.

💡

Key Point: print() (without ln) would leave the cursor on the same line — the "ln" in println is what adds the newline automatically.

Key Concepts

System.out.println()newline

Approach 2: Java 8

Java

import java.util.List;

public class PrintMultipleLinesForEach {
    public static void main(String[] args) {
        // System.out::println is shorthand for line -> System.out.println(line)
        List.of("Line 1", "Line 2", "Line 3").forEach(System.out::println);
    }
}

▶ Run Code

Output

Line 1
Line 2
Line 3

Core Logic

The three separate println() calls can collapse into one — collect the lines into a list and hand printing off to forEach().

How It Works

1List.of("Line 1", "Line 2", "Line 3") creates an immutable list holding all three lines.
2.forEach(System.out::println) calls println once per element, using a method reference instead of writing three separate statements.
3Each call to println still adds its own newline, exactly as it did when written out by hand.

forEach(System.out::println) visits "Line 1", then "Line 2", then "Line 3", printing each on its own line in list order.

💡

Key Point: System.out::println is a method reference — shorthand for the lambda line -> System.out.println(line) — and reads cleanly here because forEach hands each element straight to a method that already accepts exactly one argument.